CXF/ JAX-RS : Return Custom response from interceptor

Question

We need to return custom error code and error message when exception occurs during REST invocation. We have created a exception mapper provider, it works well for the except

Answer 1

I found a way to send a custom response from the interceptor but still can't figure out a way to call my CustomExceptionHandler from the interceptor

Code:

public void handleMessage(Message message) {

        MetadataMap metadataMap = (MetadataMap) message.get("jaxrs.template.parameters");

        if(null != metadataMap) {
            List list = metadataMap.get("phoneNumber");
            if(null != list) {
                String phoneNumber = list.get(0);
                boolean result = validatePhoneNumber(phoneNumber);
                if(!result){
// Create a response object and set it in the message. 
// calling getExchange() will not call your service
                    Response response = Response
                .status(Response.Status.BAD_REQUEST)
                .entity(new ErrorDetail(Response.Status.BAD_REQUEST.getStatusCode(), Response.Status.BAD_REQUEST.toString()))
                .build();
        message.getExchange().put(Response.class, response);
// That's it
                }
            } else {
                Response response = Response
                .status(Response.Status.BAD_REQUEST)
                .entity(new ErrorDetail(Response.Status.BAD_REQUEST.getStatusCode(), Response.Status.BAD_REQUEST.toString()))
                .build();
        message.getExchange().put(Response.class, response);
            }
        } else {
            Response response = Response
                .status(Response.Status.BAD_REQUEST)
                .entity(new ErrorDetail(Response.Status.BAD_REQUEST.getStatusCode(), Response.Status.BAD_REQUEST.toString()))
                .build();
        message.getExchange().put(Response.class, response);
        }
    }