Physical distance between two places

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悲哀的现实
悲哀的现实 2021-01-02 07:16

I need to measure the physical distance between two places whose names are provided as strings. Since sometimes the names are written slightly differently, I was looking for

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  •  温柔的废话
    2021-01-02 07:56

    I took the liberty to translate a piece of C# code I've written to calculate the Levenshtein distance into Java code. It uses only two single-dimension arrays that alternate instead of a big jagged array:

    public static int getDifference(String a, String b)
    {
        // Minimize the amount of storage needed:
        if (a.length() > b.length())
        {
            // Swap:
            String x = a;
            a = b;
            b = x;
        }
    
        // Store only two rows of the matrix, instead of a big one
        int[] mat1 = new int[a.length() + 1];
        int[] mat2 = new int[a.length() + 1];
    
        int i;
        int j;
    
        for (i = 1; i <= a.length(); i++)
            mat1[i] = i;
    
        mat2[0] = 1;
    
        for (j = 1; j <= b.length(); j++)
        {
            for (i = 1; i <= a.length(); i++)
            {
                int c = (a.charAt(i - 1) == b.charAt(j - 1) ? 0 : 1);
    
                mat2[i] =
                    Math.min(mat1[i - 1] + c,
                    Math.min(mat1[i] + 1, mat2[i - 1] + 1));
            }
    
            // Swap:
            int[] x = mat1;
            mat1 = mat2;
            mat2 = x;
    
            mat2[0] = mat1[0] + 1;
        }
    
        // It's row #1 because we swap rows at the end of each outer loop,
        // as we are to return the last number on the lowest row
        return mat1[a.length()];
    }
    

    It is not rigorously tested, but it seems to be working okay. It was based on a Python implementation I made for a university exercise. Hope this helps!

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