Java inner class visibility puzzle

Question

Consider the following case:

public class A {
  public A() { b = new B(); }
  B b;
  private class B { }
}

From a warning in Eclipse I quot

Answer 1

The access of class B and its constructor do not have to be the same. You can have a private inner class with a package-scope constructor, and this is what I usually do.

public class A {
  public A() { b = new B(); }
  B b;
  private class B {
    B() { }
  }
}