Making async for loops in Python

Question

The following code outputs as follows:

1 sec delay, print \"1\", 
1 sec delay, print \"2\", 
1 sec delay, print \"1\", 
1 sec delay, print \"2\"

Answer 1

To run the two functions simultaneously you can use gather. However, the results will be provided to you in the order you provide them. So for example if you do

results = await asyncio.gather(first(), second())

Then you will get [the result of first(), the result of second()] back. If you want to do something whenever each one returns then you should use Tasks explicitly and add callbacks.