Is there a way to enforce full initialization of std::array

Question

I am using std::array (N is a fixed template-variable).

#include
template
struct A{
   size_t fun         


        

Answer 1

You can create a wrapper for your objects

template 
struct WrapT
{
    WrapT() = delete;

    WrapT(T e)   : value(e){}

   public: T value; 
   // or add some operator()
};

and

size_t function(std::array, N> arr){ return arr[N-1].value;}

so a function call like (with full brace-init)

function({ {{1}, {2}, {3}, {4}} }); 

will not compile because of use of deleted function. Live example. The syntax is a little clumsy, and even then I'm not sure all the possible value-initialization cases are covered.

@dpy points out you may omit the innermost ones, so you get to your original code: function( {{ 1, 2, 3, 4, 5 }} ).