Rounding Numbers with bc in Bash

Question

I want to compute an average with 3 decimal figures, rounded to nearest, using bc.

For example:

average of 3, 3 and 5 should yiel

Answer 1

This solution is not that flexibile (it just converts float to int), but it can deal with negative numbers:

e=$( echo "scale=0; (${e}+0.5)/1" | bc -l )
if [[ "${e}" -lt 0 ]] ; then
    e=$(( e - 1 ))
fi