Java's strange behavior while returning from finally block

Question

Try this piece of code. Why does getValueB() return 1 instead of 2? After all, the increment() function is getting called twice.

    public class ReturningF         


        

Answer 1

You do not have an explicit return in the second example. In this case, it will return the value within the try block. It makes intuitive sense because Java has already executed the code inside the try block. It would not the executed that block again after executing the finally block.