Java printing a String containing an integer

Question

I have a doubt which follows.

public static void main(String[] args) throws IOException{
  int number=1;
  System.out.println(\"M\"+number+1);
}

Answer 1

  System.out.println("M"+number+1);

String concatination in java works this way:

if the first operand is of type String and you use + operator, it concatinates the next operand and the result would be a String.

try

 System.out.println("M"+(number+1));

In this case as the () paranthesis have the highest precedence the things inside the brackets would be evaluated first. then the resulting int value would be concatenated with the String literal resultingin a string "M2"