Java printing a String containing an integer

Question

I have a doubt which follows.

public static void main(String[] args) throws IOException{
  int number=1;
  System.out.println(\"M\"+number+1);
}

Answer 1

It has to do with the precedence order in which java concatenates the String,

Basically Java is saying

• "M"+number = "M1"
• "M1"+1 = "M11"

You can overload the precedence just like you do with maths

"M"+(number+1)

This now reads

• "M"+(number+1) = "M"+(1+1) = "M"+2 = "M2"