C - 'char **' differs in levels of indirection from 'char (*)[6]'

Question

Can someone please explain to me what\'s wrong with the following, and more importantly why?

int main( int argc, char *argv[] )
{
    char array[] = \"array\         


        

Answer 1

char **test; is a pointer to a pointer, but if you're going to take the address of an entire array then it needs to be a pointer to entire array i.e char (*test)[6];