swift - sort an array of objects by their optional boolean property without force unwrapping

Question

I can sort this array of store objects by their \'flagship\' boolean property, but how can I safely unwrap the \'flagship\' property first?

le         


        

Answer 1

As mr.Fixit pointed out on a comment, the accepted answer doesn't fully work because it doesn't take care of nils. Here is the correct answer with an extra string sample.

SWIFT 4

for a boolean sorting

 let flagshipStores = self.stores.sorted(by: {
    guard let flagship0 = $0.flagship, let flagship1 = $1.flagship else { 

       if $0.flagship == nil && $1.flagship == nil || $0.flagship != nil &&  $1.flagship == nil{

          return true

       }
       else {

          return false

       }
    } 

    return ($0.flagship == $1.flagship || $0.flagship == true && $1.flagship == false ? true : false)


 })

for strings comparison sorting

 let stores = self.stores.sorted(by: {
    guard let store0 = $0.store, let store1 = $1.store else { 

       if $0.store == nil && $1.store == nil || $0.store != nil &&  $1.store == nil{

          return true

       }
       else {

          return false

       }
    } 

    return ( ($0.store)?.localizedStandardCompare($1.store!) == ComparisonResult.orderedAscending )

 })