jQuery: use filter(), but work with both results

Question

In jQuery, filter() reduces your result to those elements that fulfill a certain condition.

This splits the list in two parts. Working with the \"good

Answer 1

You might try your hand at writing a jQuery plugin to do this. Check out the code of the filter function, and come up with something that does more precisely what you want. It could be something like:

$("some selector").processList(predicate, successCallback, failureCallback);

Then you would pass in three callbacks: one that evaluates an object to see if it matches the filter selection (you could also accept a selector string, or the like); one that handles objects that match the selection, and another that handles objects which don't match.