jQuery: use filter(), but work with both results

Question

In jQuery, filter() reduces your result to those elements that fulfill a certain condition.

This splits the list in two parts. Working with the \"good

Answer 1

The method recommended by Kobi in plugin form:

$.fn.invert = function() {
  return this.end().not(this);
};

$('.foo').filter(':visible').hide().invert().show();

Note that invert() will not add a new element to the jQuery stack but replace the last one:

$('.foo').filter(':visible').invert().end(); // this will yield $('.foo'), not $('.foo:visible')

Edit: changed prevObject to end() at Tomalak's suggestion.