IPv6 validation

前端 未结 6 958
抹茶落季
抹茶落季 2021-01-01 22:06

I used IPAddressUtil.isIPv6LiteralAddress (ipAddress) method to validate IPv6, but this method fails for ipv6-address/prefix-length format (format is mentioned

6条回答
  •  爱一瞬间的悲伤
    2021-01-01 23:02

    I had tried below regex in java and it worked for IPV4 and IPV6

    public class Utilities {
    private static Pattern VALID_IPV4_PATTERN = null;
    private static Pattern VALID_IPV6_PATTERN = null;
    private static final String ipv4Pattern = "(([01]?\\d\\d?|2[0-4]\\d|25[0-5])\\.){3}([01]?\\d\\d?|2[0-4]\\d|25[0-5])";
    private static final String ipv6Pattern = "([0-9a-f]{1,4}:){7}([0-9a-f]){1,4}";
    
    static {
    try {
      VALID_IPV4_PATTERN = Pattern.compile(ipv4Pattern, Pattern.CASE_INSENSITIVE);
      VALID_IPV6_PATTERN = Pattern.compile(ipv6Pattern, Pattern.CASE_INSENSITIVE);
       } catch (PatternSyntaxException e) {
      //logger.severe("Unable to compile pattern", e);
     }
    }
    
     /**
     * Determine if the given string is a valid IPv4 or IPv6 address.  This method
     * uses pattern matching to see if the given string could be a valid IP address.
     *
     * @param ipAddress A string that is to be examined to verify whether or not
     * it could be a valid IP address.
     * @return true if the string is a value that is a valid IP address,
     *  false otherwise.
     */
     public static boolean isIpAddress(String ipAddress) {
    
    Matcher m1 = Utilities.VALID_IPV4_PATTERN.matcher(ipAddress);
    if (m1.matches()) {
      return true;
    }
    Matcher m2 = Utilities.VALID_IPV6_PATTERN.matcher(ipAddress);
    return m2.matches();
      }
    
    
    }
    

提交回复
热议问题