I used IPAddressUtil.isIPv6LiteralAddress (ipAddress) method to validate IPv6, but this method fails for ipv6-address/prefix-length format (format is mentioned
I had tried below regex in java and it worked for IPV4 and IPV6
public class Utilities {
private static Pattern VALID_IPV4_PATTERN = null;
private static Pattern VALID_IPV6_PATTERN = null;
private static final String ipv4Pattern = "(([01]?\\d\\d?|2[0-4]\\d|25[0-5])\\.){3}([01]?\\d\\d?|2[0-4]\\d|25[0-5])";
private static final String ipv6Pattern = "([0-9a-f]{1,4}:){7}([0-9a-f]){1,4}";
static {
try {
VALID_IPV4_PATTERN = Pattern.compile(ipv4Pattern, Pattern.CASE_INSENSITIVE);
VALID_IPV6_PATTERN = Pattern.compile(ipv6Pattern, Pattern.CASE_INSENSITIVE);
} catch (PatternSyntaxException e) {
//logger.severe("Unable to compile pattern", e);
}
}
/**
* Determine if the given string is a valid IPv4 or IPv6 address. This method
* uses pattern matching to see if the given string could be a valid IP address.
*
* @param ipAddress A string that is to be examined to verify whether or not
* it could be a valid IP address.
* @return true if the string is a value that is a valid IP address,
* false otherwise.
*/
public static boolean isIpAddress(String ipAddress) {
Matcher m1 = Utilities.VALID_IPV4_PATTERN.matcher(ipAddress);
if (m1.matches()) {
return true;
}
Matcher m2 = Utilities.VALID_IPV6_PATTERN.matcher(ipAddress);
return m2.matches();
}
}