Give function defaults arguments from a dictionary in Python

Question

Let\'s imagine I have a dict :

d = {\'a\': 3, \'b\':4}

I want to create a function f that does the exact same thing than this function :

Answer 1

Sure... hope this helps

def funcc(x, **kwargs):
    locals().update(kwargs)
    print(x, a, b, c, d)

kwargs = {'a' : 1, 'b' : 2, 'c':1, 'd': 1}
x = 1

funcc(x, **kwargs)