Give function defaults arguments from a dictionary in Python

Question

Let\'s imagine I have a dict :

d = {\'a\': 3, \'b\':4}

I want to create a function f that does the exact same thing than this function :

Answer 1

How about the **kwargs trick?

def function(arg0, **kwargs):
    print("arg is", arg0, "a is", kwargs["a"], "b is", kwargs["b"])

d = {"a":1, "b":2}
function(0., **d)

outcome:

arg is 0.0 a is 1 b is 2