Give function defaults arguments from a dictionary in Python

Question

Let\'s imagine I have a dict :

d = {\'a\': 3, \'b\':4}

I want to create a function f that does the exact same thing than this function :

Answer 1

try this:

# Store the default values in a dictionary
>>> defaults = {
...     'a': 1,
...     'b': 2,
... }
>>> def f(x, **kwa):
        # Each time the function is called, merge the default values and the provided arguments
        # For python >= 3.5:
        args = {**defaults, **kwa}
        # For python < 3.5:
        # Each time the function is called, copy the default values
        args = defaults.copy()
        # Merge the provided arguments into the copied default values
        args.update(kwa)
...     print(args)
... 
>>> f(1, f=2)
{'a': 1, 'b': 2, 'f': 2}
>>> f(1, f=2, b=8)
{'a': 1, 'b': 8, 'f': 2}
>>> f(5, a=3)
{'a': 3, 'b': 2}

Thanks Olvin Roght for pointing out how to nicely merge dictionaries in python >= 3.5