Handle Arbitrary Exception, Print Default Exception Message

Question

I have a program, a part of which executes a loop. During the execution of this loop, there are exceptions. Obviously, I would like my program to run without errors, but for

Answer 1

Consider using the Python logging module, this is will give you a lot of the functionality to log problems for later inspection. Below is a simple example of using the logging module to to log exceptions:

import logging
LOG_FILE = '/tmp/exceptions.log'
logging.basicConfig(filename=LOG_FILE,level=logging.ERROR)

while True:
try:
    # Code that may throw exceptions
except Exception, e:
    logging.exception("An exception happened")

By using the logging.exception function within an exception handler as is done here the Exception info is automatically added to the logging message.