In C++11, how can I get a temporary lvalue without a name?

Question

I have a traditional C lib and a function (setsockopts) wants an argument by pointer. In C++11 (gcc 4.8), can I pass this argument without initializing a named

Answer 1

Write a function template to convert rvalues to lvalues:

template
T &as_lvalue(T &&val) {
    return val;
}

Now, use it:

deref(&as_lvalue(42));

Warning: this doesn't extend the lifetime of the temporary, so you mustn't use the returned reference after the end of the full-expression in which the temporary was created.