Scala: Constructor taking either Seq or varargs

Question

I am guessing that, for compatibility reasons, the type of vararg parameters Any* is Array[Any] - please correct this if I\'m wrong. However, this does not expl

Answer 1

No: actually, Any* is actually almost identical to Seq[Any], not to Array[Any].

To disambiguate between the two, you can use the technique to add a dummy implicit parameter to make the signature different:

class Api(api_url: String, params: Seq[(String, String)]) {
  def this(api_url: String, params: (String, String)*)(implicit d: DummyImplicit) =
    this(api_url, params)
}