I have a SQL-Server 2008 database and a schema which uses foreign key constraints to enforce referential integrity. Works as intended. Now the user creates views on the orig
It took me some time to figure out the misunderstaning here -- not sure if I still understand completely, but here it is. I will use an example, close to yours, but with some data -- easier for me to think in these terms.
So first two tables; A = Department B = Employee
CREATE TABLE Department
(
DepartmentID int PRIMARY KEY
,DepartmentName varchar(20)
,DepartmentColor varchar(10)
)
GO
CREATE TABLE Employee
(
EmployeeID int PRIMARY KEY
,EmployeeName varchar(20)
,DepartmentID int FOREIGN KEY REFERENCES Department ( DepartmentID )
)
GO
Now I'll toss some data in
INSERT INTO Department
( DepartmentID, DepartmentName, DepartmentColor )
SELECT 1, 'Accounting', 'RED' UNION
SELECT 2, 'Engineering', 'BLUE' UNION
SELECT 3, 'Sales', 'YELLOW' UNION
SELECT 4, 'Marketing', 'GREEN' ;
INSERT INTO Employee
( EmployeeID, EmployeeName, DepartmentID )
SELECT 1, 'Lyne', 1 UNION
SELECT 2, 'Damir', 2 UNION
SELECT 3, 'Sandy', 2 UNION
SELECT 4, 'Steve', 3 UNION
SELECT 5, 'Brian', 3 UNION
SELECT 6, 'Susan', 3 UNION
SELECT 7, 'Joe', 4 ;
So, now I'll create a view on the first table to filter some departments out.
CREATE VIEW dbo.BlueDepartments
AS
SELECT * FROM dbo.Department
WHERE DepartmentColor = 'BLUE'
GO
This returns
DepartmentID DepartmentName DepartmentColor
------------ -------------------- ---------------
2 Engineering BLUE
And per your example, I'll add a view for the second table which does not filter anything.
CREATE VIEW dbo.AllEmployees
AS
SELECT * FROM dbo.Employee
GO
This returns
EmployeeID EmployeeName DepartmentID
----------- -------------------- ------------
1 Lyne 1
2 Damir 2
3 Sandy 2
4 Steve 3
5 Brian 3
6 Susan 3
7 Joe 4
It seems to me that you think that Employee No 5, DepartmentID = 3 points to nowhere?
"You'll end up with entries in the second view that point nowhere."
Well, it points to the Department
table DepartmentID = 3
, as specified with the foreign key. Even if you try to join view on view nothing is broken:
SELECT e.EmployeeID
,e.EmployeeName
,d.DepartmentID
,d.DepartmentName
,d.DepartmentColor
FROM dbo.AllEmployees AS e
JOIN dbo.BlueDepartments AS d ON d.DepartmentID = e.DepartmentID
ORDER BY e.EmployeeID
Returns
EmployeeID EmployeeName DepartmentID DepartmentName DepartmentColor
----------- -------------------- ------------ -------------------- ---------------
2 Damir 2 Engineering BLUE
3 Sandy 2 Engineering BLUE
So nothing is broken here, the join simply did not find matching records for DepartmentID <> 2
This is actually the same as if I join tables and then include filter as in the first view:
SELECT e.EmployeeID
,e.EmployeeName
,d.DepartmentID
,d.DepartmentName
,d.DepartmentColor
FROM dbo.Employee AS e
JOIN dbo.Department AS d ON d.DepartmentID = e.DepartmentID
WHERE d.DepartmentColor = 'BLUE'
ORDER BY e.EmployeeID
Returns again:
EmployeeID EmployeeName DepartmentID DepartmentName DepartmentColor
----------- -------------------- ------------ -------------------- ---------------
2 Damir 2 Engineering BLUE
3 Sandy 2 Engineering BLUE
In both cases joins do not fail, they simply do as expected.
Now I will try to break the referential integrity through a view (there is no DepartmentID= 127)
INSERT INTO dbo.AllEmployees
( EmployeeID, EmployeeName, DepartmentID )
VALUES( 10, 'Bob', 127 )
And this results in:
Msg 547, Level 16, State 0, Line 1
The INSERT statement conflicted with the FOREIGN KEY constraint "FK__Employee__Depart__0519C6AF". The conflict occurred in database "Tinker_2", table "dbo.Department", column 'DepartmentID'.
If I try to delete a department through the view
DELETE FROM dbo.BlueDepartments
WHERE DepartmentID = 2
Which results in:
Msg 547, Level 16, State 0, Line 1
The DELETE statement conflicted with the REFERENCE constraint "FK__Employee__Depart__0519C6AF". The conflict occurred in database "Tinker_2", table "dbo.Employee", column 'DepartmentID'.
So constraints on underlying tables still apply.
Hope this helps, but then maybe I misunderstood your problem.