Swift 2.0 Format 1000's into a friendly K's

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陌清茗
陌清茗 2021-01-01 12:51

I\'m trying to write a function to present thousands and millions into K\'s and M\'s For instance:

1000 = 1k
1100 = 1.1k
15000 = 15k
115000 = 115k
1000000 =          


        
13条回答
  •  醉酒成梦
    2021-01-01 13:21

    Here is my approach to it.

    extension Int {
    func shorted() -> String {
        if self >= 1000 && self < 10000 {
            return String(format: "%.1fK", Double(self/100)/10).replacingOccurrences(of: ".0", with: "")
        }
    
        if self >= 10000 && self < 1000000 {
            return "\(self/1000)k"
        }
    
        if self >= 1000000 && self < 10000000 {
            return String(format: "%.1fM", Double(self/100000)/10).replacingOccurrences(of: ".0", with: "")
        }
    
        if self >= 10000000 {
            return "\(self/1000000)M"
        }
    
        return String(self)
    }
    

    Below are some examples:

    print(913.shorted())
    print(1001.shorted())
    print(1699.shorted())
    print(8900.shorted())
    print(10500.shorted())
    print(17500.shorted())
    print(863500.shorted())
    print(1200000.shorted())
    print(3010000.shorted())
    print(11800000.shorted())
    
    913
    1K
    1.6K
    8.9K
    10k
    17k
    863k
    1.2M
    3M
    11M
    

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