I\'m trying to write a function to present thousands and millions into K\'s and M\'s For instance:
1000 = 1k
1100 = 1.1k
15000 = 15k
115000 = 115k
1000000 =
To add to the answers, here's a Swift 4.X version of this using a loop to easily add/remove units if necessary:
extension Double {
var shortStringRepresentation: String {
if self.isNaN {
return "NaN"
}
if self.isInfinite {
return "\(self < 0.0 ? "-" : "+")Infinity"
}
let units = ["", "k", "M"]
var interval = self
var i = 0
while i < units.count - 1 {
if abs(interval) < 1000.0 {
break
}
i += 1
interval /= 1000.0
}
// + 2 to have one digit after the comma, + 1 to not have any.
// Remove the * and the number of digits argument to display all the digits after the comma.
return "\(String(format: "%0.*g", Int(log10(abs(interval))) + 2, interval))\(units[i])"
}
}
Examples:
$ [1.5, 15, 1000, 1470, 1000000, 1530000, 1791200000].map { $0.shortStringRepresentation }
[String] = 7 values {
[0] = "1.5"
[1] = "15"
[2] = "1k"
[3] = "1.5k"
[4] = "1M"
[5] = "1.5M"
[6] = "1791.2M"
}