canOpenURL: failed for URL: “instagram://app” - error: “This app is not allowed to query for scheme instagram”

Question

This is the code I use:

let instagramURL = NSURL(string: \"instagram://app\")
if UIApplication.shared.canOpenURL(instagramURL! as URL) {
  //Code
} else {
           


        

Answer 1

Right click on your plist file and open it as source code. Then copy and paste below code:

LSApplicationQueriesSchemes

    instagram

Note: One thing you have to keep in mind that it will not work on simulator. You need a real device for this.