pointer to const member function typedef

Question

I know it\'s possible to separate to create a pointer to member function like this

struct K { void func() {} };
typedef void FuncType();
typedef FuncType K::         


        

Answer 1

A slight refinement showing how to do it without a typedef. In a deduced context like the following, you can't use a typedef.

template 
Field extract_field(const Class& obj, Field (Class::*getter)() const)
{
   return (obj.*getter)();
}

applied to some class with a const getter:

class Foo {
 public:
  int get_int() const;
};

Foo obj;
int sz = extract_field(obj, &Foo::get_int);