How is shift operator evaluated in C?

Question

I recently noticed a (weird) behavior when I conducted operations using shift >> <<!

To explain it, let me write this small run

Answer 1

In the first example:

• a is converted to an int, shifted left, then right and then converted back to usigned char.

This will result to a=5 obviously.

In the second example:

• b is converted to int, shifted left, then converted back to unsigned char.
• b is converted to int, shifted right, then converted back to unsigned char.

The difference is that you lose information in the second example during the conversion to unsigned char