inspect.getmembers in order?

Question

inspect.getmembers(object[, predicate])

Return all the members of an object in a list of (name, value) pairs sorted by nam

Answer 1

You can dig around to find the line number for methods, not sure about other members:

import inspect

class A:
    def one(self):
        pass

    def two(self):
        pass

    def three(self):
        pass

    def four(self):
        pass

def linenumber_of_member(m):
    try:
        return m[1].__func__.__code__.co_firstlineno
    except AttributeError:
        return -1

a = A()
l = inspect.getmembers(a)
print(l)
l.sort(key=linenumber_of_member)
print(l)

prints:

[('__doc__', None), ('__module__', '__main__'), ('four', >), ('one', >), ('three', >), ('two', >)]
[('__doc__', None), ('__module__', '__main__'), ('one', >), ('two', >), ('three', >), ('four', >)]