Android PagerAdapter, get current position

Question

I want to get the current position of the visible view of my PagerAdapter

I didn\'t see an obvious function like getPosition() and I want one.

I

Answer 1

Here's an updated solution that I used myself. Since setOnPageChangeListener is now deprecated you must use addOnPageChangeListener.

viewPager.addOnPageChangeListener(new ViewPager.OnPageChangeListener() {
        @Override
        public void onPageScrolled(int position, float positionOffset, int positionOffsetPixels) {
            int counterPosition;
            if (position == 0 || position <= currentInventory.size()){
                counterPosition = position + 1;
            } else {
                counterPosition = position;
            }

            viewPagerHeader.setText("Prize " + counterPosition + " of " + currentInventory.size());

        }

        @Override
        public void onPageSelected(int position) {

        }

        @Override
        public void onPageScrollStateChanged(int state) {

        }
    });

The implementation above displays the correct index in my TextView so that positions 0 and the last item in the listcurrentInventory.size() display correctly. Hope this helps someone looking for an updated solution.