Java spread operator

Question

I am not sure of the vocabulary I am using here, please correct me if I\'m wrong.

In Javascript, I had the following code:

let args = [1,2,3];

func         


        

Answer 1

Java language does not provide an operator to do this, but its class library has a facility to do what you need.

[from OP's comment] The developer of Foo could choose himself the number of arguments that function doSomething takes. I would then be able to construct a "bag" of arguments and inject it in the method.

Use reflection API, this is what it is for. It requires you to package arguments in an array. There is a lot of extra work required, including wrapping/unwrapping individual method arguments, and method result, but you can check the signature at run-time, construct an array, and call the method.

class Test {
    public static int doSomething(int a, int b, int c) {
        return a + b + c;
    }
    // This variable holds method reference to doSomething
    private static Method doSomethingMethod;
    // We initialize this variable in a static initialization block
    static {
        try {
            doSomethingMethod = Test.class.getMethod("doSomething", Integer.TYPE, Integer.TYPE, Integer.TYPE);
        } catch (Exception e) {
        }
    }
    public static void main (String[] ignore) throws java.lang.Exception {
        // Note that args is Object[], not int[]
        Object[] args = new Object[] {1, 2, 3};
        // Result is also Object, not int
        Object res = doSomethingMethod.invoke(null, args);
        System.out.println(res);
    }
}

The above code prints 6 (demo).