C/C++: Converting hexadecimal value in char to integer

Question

I have hexadecimal values stored as characters:

char A = \'0\';
char B = \'6\';
char C = \'E\';

... I need them coverted to integers. I kno

Answer 1

int v = (A > '9')? (A &~ 0x20) - 'A' + 10: (A - '0');

is correct for ASCII. For other character sets, a similar approach would work, but you would then want toupper instead of &~ 0x20.