Grep for a word, and if found print 10 lines before and 10 lines after the pattern match

Question

I am processing a huge file. I want to search for a word in the line and when found I should print 10 lines before and 10 lines after the pattern match. How can I do it in P

Answer 1

Try this

#!/usr/bin/python
import commands

filename = "any filename"
string_to_search = "What you want to search"

extract  = (commands.getstatusoutput("grep -C 10 '%s' %s"%(string_to_search,filename)))[1]

print(extract)