ES6 Template Literals: How to pass a scope before they are interpreted?

Question

I am starting to use template literals to make a error generator.

I have working code, but I am forced to declare the list of possible errors inside the constr

Answer 1

It's a darn shame that template literals aren't more flexible.

Here are two methods that may be close to what you want.

First:

var s = (item, price) => {return `item: ${item}, price: $${price}`}
s('pants', 10) // 'item: pants, price: $10'
s('shirts', 15) // 'item: shirts, price: $15'

To generalify:

var s = () => {return `