Brute force script in Python 3.2

Question

I\'m a beginner in writing code and I\'ve started with Python because it seemed the neatest and the easiest to start with (I currently have Python 3.2). Now I\'ve read some

Answer 1

Code first:

from itertools import product

chars = '0123456789' # chars to look for

for length in range(1, 3): # only do lengths of 1 + 2
    to_attempt = product(chars, repeat=length)
    for attempt in to_attempt:
        print(''.join(attempt))

itertools.product produces a Cartesian join of its input(s) - in this case, it's being 'joined' to itself. So in the first iteration, each single character is printed. Then in the next iteration, because of repeat=length (and length is now == 2), generates '00', '01', etc... It's worth trying it and seeing the output to understand it better.

This also means you can throw in letters (uppercase/lowercase), and change the upperbound in the range function.

It's certainly not going to break the world of code-breaking, but should give you an idea of the flexibility of Python and the tools available to you.

I'll leave you to check the passwords match and break out the loop.