I have a poll on my website which displays radio buttons next to each answer. When the user selects an option and submits, im running a a php script via ajax to insert the v
var option = $('input[type="radio"]:checked').val();
$.ajax({
type: "POST",
url: "ajax_submit_vote.php",
data: { poll_option : option }
});
In the PHP you are reading $_POST['poll_option']
therefore you must use poll_option
as the key in your data object. Also, the value is stored in option
not $optionID
as you were trying to use.
The $
is a valid character in variable names in Javascript, it doesn't do anything special itself but some coders prefix anything that is a jQuery object with $
so they can glance through code and easily see what variables already have the jQuery wrapper.
For example:
var $option = $('input[type="radio"]:checked'); // $option is the jQuery wrapped HTML element
var myValue = $option.val(); // we know $option already has the jQuery wrapper so no need to use the $(..) syntax.