Generating circular shifts / reduced Latin Squares in Python

Question

Was just wondering what\'s the most efficient way of generating all the circular shifts of a list in Python. In either direction. For example, given a list [1, 2, 3, 4

Answer 1

This will be my solution.

#given list
a = [1,2,3,4]
#looping through list
for i in xrange(len(a)):
    #inserting last element at the starting
    a.insert(0,a[len(a)-1])
    #removing the last element
    a = a[:len(a)-1]
    #printing if you want to
    print a

This will output the following:

[4, 1, 2, 3]
[3, 4, 1, 2]
[2, 3, 4, 1]
[1, 2, 3, 4]

You can also use pop instead of using list slicing but the problem with pop is that it will return something.

Also the above code will work for any length of list. I have not checked for performance of the code. I am assuming that it will work better.

You should have a look at Python docs for getting a good understanding of List slicing.