In a project I am currently working on I have implemented about 80% of what I want my program to do and I am very happy with the results.
In the remaining 20% I am f
I'd use a generator:
import itertools
def comb(seq):
for n in range(1, len(seq)):
for c in itertools.combinations(seq, n): # all combinations of length n
if len(set.union(*map(set, c))) == sum(len(s) for s in c): # pairwise disjoint?
yield list(c)
for c in comb([[1, 2, 3], [3, 6, 8], [4, 9], [6, 11]]):
print c
This produces:
[[1, 2, 3]]
[[3, 6, 8]]
[[4, 9]]
[[6, 11]]
[[1, 2, 3], [4, 9]]
[[1, 2, 3], [6, 11]]
[[3, 6, 8], [4, 9]]
[[4, 9], [6, 11]]
[[1, 2, 3], [4, 9], [6, 11]]
If you need to store the results in a single list:
print list(comb([[1, 2, 3], [3, 6, 8], [4, 9], [6, 11]]))