what is the reason for fopen's failure to open a file

Question

I have the following code where I am trying to open a text file.

char frd[32]=\"word-list.txt\";
   FILE *rd=fopen(frd,\"rb\");
   if(!rd)
       std::cout&         


        

Answer 1

#include
#include 

int main()
{
errno = 0;
FILE *fb = fopen("/home/jeegar/filename","r");
if(fb==NULL)
    printf("its null");
else
    printf("working");


printf("Error %d \n", errno);


}

this way if fopen gets fail then it will set error number you can find those error number list at here http://pubs.opengroup.org/onlinepubs/009695399/functions/fopen.html