Select last child when odd, 2 last childs when even

Question

I\'m in a situation where the number of elements showed is variable, and I need a strange solution which I\'m not able to achieve, I even doubt if it\'s achievable only with

Answer 1

Here is one way...

.wrap div:last-child,
.wrap div:nth-last-of-type(-n+2):not(:nth-child(even)) {
    color: red;
}

    
Odd
    
Even
    
Odd
    
Even
    
Odd
    
Even





    
Odd
    
Even
    
Odd
    
Even
    
Odd