How to use python socket.settimeout() properly

Question

As far as I know, when you call socket.settimeout(value) and you set a float value greater than 0.0, that socket will raise a scocket.timeout when a call to, fo

Answer 1

See my server script, you will get the idea to use it properly.

import socket
import sys
fragments = []
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.bind(("192.168.1.4",9001))
s.listen(5)
while True:
    c,a = s.accept()
    c.settimeout(10.0)
    print "Someone came in Server from %s and port %s" %(a[0],a[1])
    c.send("Welcome to system")
    while True:
        chunk = c.recv(2048)
        if not chunk.strip():
            break
        else:
            fragments.append(chunk)
            continue
    combiner = "".join(fragments)
    print combiner
    shutdown = str(raw_input("Wanna Quit(Y/y) or (N/n): "))
    if shutdown == 'Y' or shutdown == 'y':
        c.close()
        sys.exit()
    else:
        continue

This script is just to give you an idea about the socket.settimeout().