Call derived class method from base class reference

Question

class Material
{
public:
 void foo()
 {
  cout << \"Class Material\";
 }
};

class Unusual_Material : public Material
{
public:
 void foo()
 {
  cout <<          


        

Answer 1

Still better explanation would be..

class Base
{
public:
 void foo()     //make virtual void foo(),have derived method invoked
 {
  cout << "Class Base";
 }
};
class Derived: public Base
{
public:
 void foo()
 {
  cout << "Class Derived";
 }
};
int main()
{
 Base base1 = Derived ();
 Base1.foo(); //outputs "Class Base" 
           // Base object, calling base method

 Base *base2 = new Derived ();
 Base2->foo(); //outputs"Class Base",Again Base object calling base method

// But to have base object, calling Derived method, following are the ways
// Add virtual access modifier for base foo() method. Then do as below, to //have derived method being invoked.
//
// Base *base2 = new Derived ();
// Base2->foo();    //outputs "Class Derived" .

return 0;
}