JavaScript if(x) vs if(x==true)

Question

In JavaScript , in which cases the following statements won\'t be logically equal ?

if(x){}

and

if(x==true){}

Answer 1

Several cases evaluate to false in the first form, such as empty string, 0, undefined, null.

If you want to be a bit more semantic about it, try the bang bang in front of the expression:

if(!!x){...}

this will convert the expression result to a truthy representing the same semantically. This is closer to an analogue to the expression you describe (x == true)

Also be aware that == is value comparions with type coercion, eg "3" == 3, whereas === asserts equal typing too.

So they are not the same, but often logically represent the same test, thanks to the semantics of the language and the !! you can use