For instance, if I have a list
[1,4,2,3,5,4,5,6,7,8,1,3,4,5,9,10,11]
This algorithm should return [1,2,3,4,5,6,7,8,9,10,11].
To cl
Warning: This is the cheaty way to do it (aka I use python...)
import operator as op
import itertools as it
def longestSequence(data):
longest = []
for k, g in it.groupby(enumerate(set(data)), lambda(i, y):i-y):
thisGroup = map(op.itemgetter(1), g)
if len(thisGroup) > len(longest):
longest = thisGroup
return longest
longestSequence([1,4,2,3,5,4,5,6,7,8,1,3,4,5,9,10,11, 15,15,16,17,25])