For instance, if I have a list
[1,4,2,3,5,4,5,6,7,8,1,3,4,5,9,10,11]
This algorithm should return [1,2,3,4,5,6,7,8,9,10,11].
To cl
Not that clever, not O(n), could use a bit of optimization. But it works.
def longest(seq): result = [] for v in seq: for l in result: if v == l[-1] + 1: l.append(v) else: result.append([v]) return max(result, key=len)