How to handle ajax 201

Question

When making a ajax call see example below success does gets a 201 status retuned. How do you handle these better i.e. 200, 201 within the succe

Answer 1

Use the statusCode object:

var handle200 = function(data, textStatus, jqXHR) {
    alert('200'); // success codes have the success signature
};

var handle201 = function(data, textStatus, jqXHR) {
    alert('201'); // success codes have the success signature
    // test it if you are in doubt:
    console.log(data);
    console.log(textStatus);
    console.log(jqXHR);
};

var handle404 = function(jqXHR, textStatus, errorThrown) {
    alert('404'); // failing codes have the error signature
});

var request = $.ajax({
    type: 'POST',
    url: '/myresource/posttarget',
    data: { name: 'john' },
    statusCode: {
        200: handle200,
        201: handle201,
        404: handle404
    }
});