I\'m looking for advice on the best way to proceed. I\'m trying to find whether a given point A:(a, b) is inside a regular hexagon, defined with center O:(x, y) and diameter
This is what I have been using:
public bool InsideHexagon(float x, float y)
{
// Check length (squared) against inner and outer radius
float l2 = x * x + y * y;
if (l2 > 1.0f) return false;
if (l2 < 0.75f) return true; // (sqrt(3)/2)^2 = 3/4
// Check against borders
float px = x * 1.15470053838f; // 2/sqrt(3)
if (px > 1.0f || px < -1.0f) return false;
float py = 0.5f * px + y;
if (py > 1.0f || py < -1.0f) return false;
if (px - py > 1.0f || px - py < -1.0f) return false;
return true;
}
px and py are the coordinates of x and y projected onto a coordinate system where it is much easier to check the boundaries.
