early return from a void-func in Swift?

Question

Can someone explain me the following behaviour in Swift?

func test() -> Bool {
    print(\"1 before return\")
    return false
    print(\"1 after return\         


        

Answer 1

Answer extracted from question:

It seems the problem is, that swift does not exit the function instantly on a return statement in a void function and uses the consecutive void value as the function parameter and terminates as expected if it is non-void.

Code after 'return' will never be executed

[...]
return; // <- would return here

[...]
return () // <- would return here

[...]
return // <- would return here
let x = 42

If Xcode would work reliably this message should be shown on the next examples:

Expression following 'return' is treated as an argument of the 'return'

[...]
return
print("oh no") // <- would return here

[...]
return
myClosure("this feels wrong") // <- would return here and execute the function / closure

This issue is already in the Swift-bug-tracker since 2016: https://bugs.swift.org/browse/SR-2028