How can I create a GzipFile instance from the “file-like object” that urllib.urlopen() returns?

Question

I’m playing around with the Stack Overflow API using Python. I’m trying to decode the gzipped responses that the API gives.

import urllib, gzip

url = urllib         


        

Answer 1

Here is a new update for @stefanw's answer, to whom that might think it too expensive to use that much memory.

Thanks to this article(https://www.enricozini.org/blog/2011/cazzeggio/python-gzip/, it explains why gzip doesn't work), the solution is to use Python3.

import urllib.request
import gzip

response = urllib.request.urlopen('http://api.stackoverflow.com/1.0/badges/name')
with gzip.GzipFile(fileobj=response) as f:
    for line in f:
        print(line)