String initialization with and without explicit trailing terminator

Question

What is the difference between

char str1[32] = \"\\0\";

and

char str2[32] = \"\";

Answer 1

Unless I'm mistaken, the first will initialize 2 chars to 0 (the '\0' and the terminator that's always there, and leave the rest untouched, and the last will initialize only 1 char (the terminator).