SQL Server - GROUP BY on one column

Question

I\'m trying to get orders from an orderview. In my view I do have some rows with exactly the same values, but I want to group these values on orderid and take the sum of the

Answer 1

You could use a CTE with SUM(Quantity)OVER(PARTITION BY Order_id) + ROW_NUMBER to pick out the desired row from the order-group:

WITH cte 
     AS (SELECT order_id, 
                customer_id, 
                article_id, 
                delivery_date, 
                quantity=Sum(quantity) 
                           OVER( 
                             partition BY order_id), 
                rn = Row_number() 
                       OVER( 
                         partition BY order_id 
                         ORDER BY delivery_date ASC) 
         FROM   orders) 
SELECT order_id, 
       customer_id, 
       article_id, 
       delivery_date, 
       quantity 
FROM   cte 
WHERE  rn = 1 

DEMO

However, your desired result seems to be incorrect (question edited)

This is my result:

ORDER_ID    CUSTOMER_ID ARTICLE_ID  DELIVERY_DATE   QUANTITY
PR10.001    11          20.001a         17-04-2013  3
PR13.001    15          41.022b         19-04-2013  2