C++, get the name of the function

Question

In C++, is there a way to get the function signature/name from it\'s pointer like this?

void test(float data) {}
cout << typeid(&test).name();
         


        

Answer 1

I'm not 100% sure, but this seems to me like reflection (Java), and C++ does not support things like this. It may be that I just don't know,but i havent seen this for C++ yet.